3(5j+1)+j=3(2j+1)+8

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Solution for 3(5j+1)+j=3(2j+1)+8 equation: 


Simplifying
3(5j + 1) + j = 3(2j + 1) + 8

Reorder the terms:
3(1 + 5j) + j = 3(2j + 1) + 8
(1 * 3 + 5j * 3) + j = 3(2j + 1) + 8
(3 + 15j) + j = 3(2j + 1) + 8

Combine like terms: 15j + j = 16j
3 + 16j = 3(2j + 1) + 8

Reorder the terms:
3 + 16j = 3(1 + 2j) + 8
3 + 16j = (1 * 3 + 2j * 3) + 8
3 + 16j = (3 + 6j) + 8

Reorder the terms:
3 + 16j = 3 + 8 + 6j

Combine like terms: 3 + 8 = 11
3 + 16j = 11 + 6j

Solving
3 + 16j = 11 + 6j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-6j' to each side of the equation.
3 + 16j + -6j = 11 + 6j + -6j

Combine like terms: 16j + -6j = 10j
3 + 10j = 11 + 6j + -6j

Combine like terms: 6j + -6j = 0
3 + 10j = 11 + 0
3 + 10j = 11

Add '-3' to each side of the equation.
3 + -3 + 10j = 11 + -3

Combine like terms: 3 + -3 = 0
0 + 10j = 11 + -3
10j = 11 + -3

Combine like terms: 11 + -3 = 8
10j = 8

Divide each side by '10'.
j = 0.8

Simplifying
j = 0.8

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