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3(5j+5)=2(3j-6)
We move all terms to the left:
3(5j+5)-(2(3j-6))=0
We multiply parentheses
15j-(2(3j-6))+15=0
We calculate terms in parentheses: -(2(3j-6)), so:We get rid of parentheses
2(3j-6)
We multiply parentheses
6j-12
Back to the equation:
-(6j-12)
15j-6j+12+15=0
We add all the numbers together, and all the variables
9j+27=0
We move all terms containing j to the left, all other terms to the right
9j=-27
j=-27/9
j=-3
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