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3(5k+7)+2(3k-5)=5(2k+11)
We move all terms to the left:
3(5k+7)+2(3k-5)-(5(2k+11))=0
We multiply parentheses
15k+6k-(5(2k+11))+21-10=0
We calculate terms in parentheses: -(5(2k+11)), so:We add all the numbers together, and all the variables
5(2k+11)
We multiply parentheses
10k+55
Back to the equation:
-(10k+55)
21k-(10k+55)+11=0
We get rid of parentheses
21k-10k-55+11=0
We add all the numbers together, and all the variables
11k-44=0
We move all terms containing k to the left, all other terms to the right
11k=44
k=44/11
k=4
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