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3(5p-1)-4(3p-7)p=4.
We move all terms to the left:
3(5p-1)-4(3p-7)p-(4.)=0
We add all the numbers together, and all the variables
3(5p-1)-4(3p-7)p-4=0
We multiply parentheses
-12p^2+15p+28p-3-4=0
We add all the numbers together, and all the variables
-12p^2+43p-7=0
a = -12; b = 43; c = -7;
Δ = b2-4ac
Δ = 432-4·(-12)·(-7)
Δ = 1513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{1513}}{2*-12}=\frac{-43-\sqrt{1513}}{-24} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{1513}}{2*-12}=\frac{-43+\sqrt{1513}}{-24} $
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