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3(5q-4)=2(4q+5)
We move all terms to the left:
3(5q-4)-(2(4q+5))=0
We multiply parentheses
15q-(2(4q+5))-12=0
We calculate terms in parentheses: -(2(4q+5)), so:We get rid of parentheses
2(4q+5)
We multiply parentheses
8q+10
Back to the equation:
-(8q+10)
15q-8q-10-12=0
We add all the numbers together, and all the variables
7q-22=0
We move all terms containing q to the left, all other terms to the right
7q=22
q=22/7
q=3+1/7
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