3(5r-4)=-7+5(r+1)

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Solution for 3(5r-4)=-7+5(r+1) equation: 



3(5r-4)=-7+5(r+1)

We move all terms to the left:

3(5r-4)-(-7+5(r+1))=0

We multiply parentheses

15r-(-7+5(r+1))-12=0



We calculate terms in parentheses: -(-7+5(r+1)), so:

-7+5(r+1)

determiningTheFunctionDomain
5(r+1)-7

We multiply parentheses

5r+5-7

We add all the numbers together, and all the variables

5r-2

Back to the equation:

-(5r-2)



We get rid of parentheses

15r-5r+2-12=0

We add all the numbers together, and all the variables

10r-10=0

We move all terms containing r to the left, all other terms to the right

10r=10

r=10/10

r=1

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