3(5s-2)-4(2s+7)=200s-1964

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Solution for 3(5s-2)-4(2s+7)=200s-1964 equation: 



3(5s-2)-4(2s+7)=200s-1964

We move all terms to the left:

3(5s-2)-4(2s+7)-(200s-1964)=0

We multiply parentheses

15s-8s-(200s-1964)-6-28=0

We get rid of parentheses

15s-8s-200s+1964-6-28=0

We add all the numbers together, and all the variables

-193s+1930=0

We move all terms containing s to the left, all other terms to the right

-193s=-1930

s=-1930/-193

s=+10

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