3(5t-6)=29t+7

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Solution for 3(5t-6)=29t+7 equation: 



3(5t-6)=29t+7

We move all terms to the left:

3(5t-6)-(29t+7)=0

We multiply parentheses

15t-(29t+7)-18=0

We get rid of parentheses

15t-29t-7-18=0

We add all the numbers together, and all the variables

-14t-25=0

We move all terms containing t to the left, all other terms to the right

-14t=25

t=25/-14

t=-1+11/14

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