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3(5x+1)-11x-9=6(3x-1)-2(15-x)
We move all terms to the left:
3(5x+1)-11x-9-(6(3x-1)-2(15-x))=0
We add all the numbers together, and all the variables
3(5x+1)-11x-(6(3x-1)-2(-1x+15))-9=0
We add all the numbers together, and all the variables
-11x+3(5x+1)-(6(3x-1)-2(-1x+15))-9=0
We multiply parentheses
-11x+15x-(6(3x-1)-2(-1x+15))+3-9=0
We calculate terms in parentheses: -(6(3x-1)-2(-1x+15)), so:We add all the numbers together, and all the variables
6(3x-1)-2(-1x+15)
We multiply parentheses
18x+2x-6-30
We add all the numbers together, and all the variables
20x-36
Back to the equation:
-(20x-36)
4x-(20x-36)-6=0
We get rid of parentheses
4x-20x+36-6=0
We add all the numbers together, and all the variables
-16x+30=0
We move all terms containing x to the left, all other terms to the right
-16x=-30
x=-30/-16
x=1+7/8
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