3(5x+1)-47=10x-4

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Solution for 3(5x+1)-47=10x-4 equation: 



3(5x+1)-47=10x-4

We move all terms to the left:

3(5x+1)-47-(10x-4)=0

We multiply parentheses

15x-(10x-4)+3-47=0

We get rid of parentheses

15x-10x+4+3-47=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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