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3(5x+20)=2(3x-6)
We move all terms to the left:
3(5x+20)-(2(3x-6))=0
We multiply parentheses
15x-(2(3x-6))+60=0
We calculate terms in parentheses: -(2(3x-6)), so:We get rid of parentheses
2(3x-6)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
15x-6x+12+60=0
We add all the numbers together, and all the variables
9x+72=0
We move all terms containing x to the left, all other terms to the right
9x=-72
x=-72/9
x=-8
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