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3(5x+4)-20=2(x+3)
We move all terms to the left:
3(5x+4)-20-(2(x+3))=0
We multiply parentheses
15x-(2(x+3))+12-20=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
15x-(2x+6)-8=0
We get rid of parentheses
15x-2x-6-8=0
We add all the numbers together, and all the variables
13x-14=0
We move all terms containing x to the left, all other terms to the right
13x=14
x=14/13
x=1+1/13
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