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3(5x+4)=10-2(8-3x)
We move all terms to the left:
3(5x+4)-(10-2(8-3x))=0
We add all the numbers together, and all the variables
3(5x+4)-(10-2(-3x+8))=0
We multiply parentheses
15x-(10-2(-3x+8))+12=0
We calculate terms in parentheses: -(10-2(-3x+8)), so:We get rid of parentheses
10-2(-3x+8)
determiningTheFunctionDomain -2(-3x+8)+10
We multiply parentheses
6x-16+10
We add all the numbers together, and all the variables
6x-6
Back to the equation:
-(6x-6)
15x-6x+6+12=0
We add all the numbers together, and all the variables
9x+18=0
We move all terms containing x to the left, all other terms to the right
9x=-18
x=-18/9
x=-2
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