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3(5x+6x-10)=5(2x+40)
We move all terms to the left:
3(5x+6x-10)-(5(2x+40))=0
We add all the numbers together, and all the variables
3(11x-10)-(5(2x+40))=0
We multiply parentheses
33x-(5(2x+40))-30=0
We calculate terms in parentheses: -(5(2x+40)), so:We get rid of parentheses
5(2x+40)
We multiply parentheses
10x+200
Back to the equation:
-(10x+200)
33x-10x-200-30=0
We add all the numbers together, and all the variables
23x-230=0
We move all terms containing x to the left, all other terms to the right
23x=230
x=230/23
x=10
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