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3(5x-2)+4x=3(3x+2)-2x
We move all terms to the left:
3(5x-2)+4x-(3(3x+2)-2x)=0
We add all the numbers together, and all the variables
4x+3(5x-2)-(3(3x+2)-2x)=0
We multiply parentheses
4x+15x-(3(3x+2)-2x)-6=0
We calculate terms in parentheses: -(3(3x+2)-2x), so:We add all the numbers together, and all the variables
3(3x+2)-2x
We add all the numbers together, and all the variables
-2x+3(3x+2)
We multiply parentheses
-2x+9x+6
We add all the numbers together, and all the variables
7x+6
Back to the equation:
-(7x+6)
19x-(7x+6)-6=0
We get rid of parentheses
19x-7x-6-6=0
We add all the numbers together, and all the variables
12x-12=0
We move all terms containing x to the left, all other terms to the right
12x=12
x=12/12
x=1
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