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3(5x-2)-2=5(2x+1)+3x-1
We move all terms to the left:
3(5x-2)-2-(5(2x+1)+3x-1)=0
We multiply parentheses
15x-(5(2x+1)+3x-1)-6-2=0
We calculate terms in parentheses: -(5(2x+1)+3x-1), so:We add all the numbers together, and all the variables
5(2x+1)+3x-1
We add all the numbers together, and all the variables
3x+5(2x+1)-1
We multiply parentheses
3x+10x+5-1
We add all the numbers together, and all the variables
13x+4
Back to the equation:
-(13x+4)
15x-(13x+4)-8=0
We get rid of parentheses
15x-13x-4-8=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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