3(5x-2)-4(x+4)=7(x+1)+1

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Solution for 3(5x-2)-4(x+4)=7(x+1)+1 equation: 



3(5x-2)-4(x+4)=7(x+1)+1

We move all terms to the left:

3(5x-2)-4(x+4)-(7(x+1)+1)=0

We multiply parentheses

15x-4x-(7(x+1)+1)-6-16=0



We calculate terms in parentheses: -(7(x+1)+1), so:

7(x+1)+1

We multiply parentheses

7x+7+1

We add all the numbers together, and all the variables

7x+8

Back to the equation:

-(7x+8)



We add all the numbers together, and all the variables

11x-(7x+8)-22=0

We get rid of parentheses

11x-7x-8-22=0

We add all the numbers together, and all the variables

4x-30=0

We move all terms containing x to the left, all other terms to the right

4x=30

x=30/4

x=7+1/2

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