3(5y+2)-y=2(y-2)

Solution for 3(5y+2)-y=2(y-2) equation:

3(5y+2)-y=2(y-2)

We move all terms to the left:

3(5y+2)-y-(2(y-2))=0

We add all the numbers together, and all the variables

-1y+3(5y+2)-(2(y-2))=0

We multiply parentheses

-1y+15y-(2(y-2))+6=0


We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)


We add all the numbers together, and all the variables

14y-(2y-4)+6=0

We get rid of parentheses

14y-2y+4+6=0

We add all the numbers together, and all the variables

12y+10=0

We move all terms containing y to the left, all other terms to the right

12y=-10

y=-10/12

y=-5/6