3(5y+4)-20=13y-4

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Solution for 3(5y+4)-20=13y-4 equation: 



3(5y+4)-20=13y-4

We move all terms to the left:

3(5y+4)-20-(13y-4)=0

We multiply parentheses

15y-(13y-4)+12-20=0

We get rid of parentheses

15y-13y+4+12-20=0

We add all the numbers together, and all the variables

2y-4=0

We move all terms containing y to the left, all other terms to the right

2y=4

y=4/2

y=2

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