3(5y-2)-4(y+4)=7(y-1)+1

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Solution for 3(5y-2)-4(y+4)=7(y-1)+1 equation: 



35y-2-4y+4=7y-1+1

We move all terms to the left:

35y-2-4y+4-(7y-1+1)=0

We add all the numbers together, and all the variables

35y-4y-(+7y)-2+4=0

We add all the numbers together, and all the variables

31y-(+7y)+2=0

We get rid of parentheses

31y-7y+2=0

We add all the numbers together, and all the variables

24y+2=0

We move all terms containing y to the left, all other terms to the right

24y=-2

y=-2/24

y=-1/12

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