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3(5y-3)-25=13-(2y-3)
We move all terms to the left:
3(5y-3)-25-(13-(2y-3))=0
We multiply parentheses
15y-(13-(2y-3))-9-25=0
We calculate terms in parentheses: -(13-(2y-3)), so:We add all the numbers together, and all the variables
13-(2y-3)
determiningTheFunctionDomain -(2y-3)+13
We get rid of parentheses
-2y+3+13
We add all the numbers together, and all the variables
-2y+16
Back to the equation:
-(-2y+16)
15y-(-2y+16)-34=0
We get rid of parentheses
15y+2y-16-34=0
We add all the numbers together, and all the variables
17y-50=0
We move all terms containing y to the left, all other terms to the right
17y=50
y=50/17
y=2+16/17
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