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3(5y-4)+3(1-3y)=(2y-3)
We move all terms to the left:
3(5y-4)+3(1-3y)-((2y-3))=0
We add all the numbers together, and all the variables
3(5y-4)+3(-3y+1)-((2y-3))=0
We multiply parentheses
15y-9y-((2y-3))-12+3=0
We calculate terms in parentheses: -((2y-3)), so:We add all the numbers together, and all the variables
(2y-3)
We get rid of parentheses
2y-3
Back to the equation:
-(2y-3)
6y-(2y-3)-9=0
We get rid of parentheses
6y-2y+3-9=0
We add all the numbers together, and all the variables
4y-6=0
We move all terms containing y to the left, all other terms to the right
4y=6
y=6/4
y=1+1/2
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