3(5z+1)-2(z+4)=

Solution for 3(5z+1)-2(z+4)= equation:

Simplifying
3(5z + 1) + -2(z + 4) = 0

Reorder the terms:
3(1 + 5z) + -2(z + 4) = 0
(1 * 3 + 5z * 3) + -2(z + 4) = 0
(3 + 15z) + -2(z + 4) = 0

Reorder the terms:
3 + 15z + -2(4 + z) = 0
3 + 15z + (4 * -2 + z * -2) = 0
3 + 15z + (-8 + -2z) = 0

Reorder the terms:
3 + -8 + 15z + -2z = 0

Combine like terms: 3 + -8 = -5
-5 + 15z + -2z = 0

Combine like terms: 15z + -2z = 13z
-5 + 13z = 0

Solving
-5 + 13z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 13z = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 13z = 0 + 5
13z = 0 + 5

Combine like terms: 0 + 5 = 5
13z = 5

Divide each side by '13'.
z = 0.3846153846

Simplifying
z = 0.3846153846