3(5z+1)-6=102

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Solution for 3(5z+1)-6=102 equation: 



3(5z+1)-6=102

We move all terms to the left:

3(5z+1)-6-(102)=0

We add all the numbers together, and all the variables

3(5z+1)-108=0

We multiply parentheses

15z+3-108=0

We add all the numbers together, and all the variables

15z-105=0

We move all terms containing z to the left, all other terms to the right

15z=105

z=105/15

z=7

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