3(5z+2)=4(3z+5)

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Solution for 3(5z+2)=4(3z+5) equation: 



3(5z+2)=4(3z+5)

We move all terms to the left:

3(5z+2)-(4(3z+5))=0

We multiply parentheses

15z-(4(3z+5))+6=0



We calculate terms in parentheses: -(4(3z+5)), so:

4(3z+5)

We multiply parentheses

12z+20

Back to the equation:

-(12z+20)



We get rid of parentheses

15z-12z-20+6=0

We add all the numbers together, and all the variables

3z-14=0

We move all terms containing z to the left, all other terms to the right

3z=14

z=14/3

z=4+2/3

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