3(5z-(3))-(4(2z+1))=5z-(2)

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Solution for 3(5z-(3))-(4(2z+1))=5z-(2) equation: 



3(5z-(3))-(4(2z+1))=5z-(2)

We move all terms to the left:

3(5z-(3))-(4(2z+1))-(5z-(2))=0

We multiply parentheses

15z-(4(2z+1))-(5z-2)-9=0

We get rid of parentheses

15z-(4(2z+1))-5z+2-9=0



We calculate terms in parentheses: -(4(2z+1)), so:

4(2z+1)

We multiply parentheses

8z+4

Back to the equation:

-(8z+4)



We add all the numbers together, and all the variables

10z-(8z+4)-7=0

We get rid of parentheses

10z-8z-4-7=0

We add all the numbers together, and all the variables

2z-11=0

We move all terms containing z to the left, all other terms to the right

2z=11

z=11/2

z=5+1/2

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