3(6+1.75y)-7y=32

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Solution for 3(6+1.75y)-7y=32 equation: 



3(6+1.75y)-7y=32

We move all terms to the left:

3(6+1.75y)-7y-(32)=0

We add all the numbers together, and all the variables

3(1.75y+6)-7y-32=0

We add all the numbers together, and all the variables

-7y+3(1.75y+6)-32=0

We multiply parentheses

-7y+3y+18-32=0

We add all the numbers together, and all the variables

-4y-14=0

We move all terms containing y to the left, all other terms to the right

-4y=14

y=14/-4

y=-3+1/2

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