3(6+2x)=4(3x+12)

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Solution for 3(6+2x)=4(3x+12) equation: 



3(6+2x)=4(3x+12)

We move all terms to the left:

3(6+2x)-(4(3x+12))=0

We add all the numbers together, and all the variables

3(2x+6)-(4(3x+12))=0

We multiply parentheses

6x-(4(3x+12))+18=0



We calculate terms in parentheses: -(4(3x+12)), so:

4(3x+12)

We multiply parentheses

12x+48

Back to the equation:

-(12x+48)



We get rid of parentheses

6x-12x-48+18=0

We add all the numbers together, and all the variables

-6x-30=0

We move all terms containing x to the left, all other terms to the right

-6x=30

x=30/-6

x=-5

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