3(6+3x)=(1)/(27)

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Solution for 3(6+3x)=(1)/(27) equation: 



3(6+3x)=(1)/(27)

We move all terms to the left:

3(6+3x)-((1)/(27))=0

We add all the numbers together, and all the variables

3(3x+6)-(+1/27)=0

We multiply parentheses

9x+18-(+1/27)=0

We get rid of parentheses

9x+18-1/27=0

We multiply all the terms by the denominator


9x*27-1+18*27=0

We add all the numbers together, and all the variables

9x*27+485=0

Wy multiply elements

243x+485=0

We move all terms containing x to the left, all other terms to the right

243x=-485

x=-485/243

x=-1+242/243

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