3(6+4/5b)=(9/10b)3

Solution for 3(6+4/5b)=(9/10b)3 equation:

3(6+4/5b)=(9/10b)3

We move all terms to the left:

3(6+4/5b)-((9/10b)3)=0


Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R



Domain of the equation: 10b)3)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

3(4/5b+6)-((+9/10b)3)=0

We multiply parentheses

12b-((+9/10b)3)+18=0

We multiply all the terms by the denominator


12b*10b)3)-((+18*10b)3)+9=0

Wy multiply elements

120b^2+180b=0

a = 120; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·120·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*120}=\frac{-360}{240}
=-1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*120}=\frac{0}{240}
=0
$