3(6+4y)+10y=7

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Solution for 3(6+4y)+10y=7 equation:



3(6+4y)+10y=7
We move all terms to the left:
3(6+4y)+10y-(7)=0
We add all the numbers together, and all the variables
3(4y+6)+10y-7=0
We add all the numbers together, and all the variables
10y+3(4y+6)-7=0
We multiply parentheses
10y+12y+18-7=0
We add all the numbers together, and all the variables
22y+11=0
We move all terms containing y to the left, all other terms to the right
22y=-11
y=-11/22
y=-1/2

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