3(6+5y)=2(4y-5)

Solution for 3(6+5y)=2(4y-5) equation:

3(6+5y)=2(4y-5)

We move all terms to the left:

3(6+5y)-(2(4y-5))=0

We add all the numbers together, and all the variables

3(5y+6)-(2(4y-5))=0

We multiply parentheses

15y-(2(4y-5))+18=0


We calculate terms in parentheses: -(2(4y-5)), so:

2(4y-5)

We multiply parentheses

8y-10

Back to the equation:

-(8y-10)


We get rid of parentheses

15y-8y+10+18=0

We add all the numbers together, and all the variables

7y+28=0

We move all terms containing y to the left, all other terms to the right

7y=-28

y=-28/7

y=-4