3(6+5y)=7(-5+4y)

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Solution for 3(6+5y)=7(-5+4y) equation: 



3(6+5y)=7(-5+4y)

We move all terms to the left:

3(6+5y)-(7(-5+4y))=0

We add all the numbers together, and all the variables

3(5y+6)-(7(4y-5))=0

We multiply parentheses

15y-(7(4y-5))+18=0



We calculate terms in parentheses: -(7(4y-5)), so:

7(4y-5)

We multiply parentheses

28y-35

Back to the equation:

-(28y-35)



We get rid of parentheses

15y-28y+35+18=0

We add all the numbers together, and all the variables

-13y+53=0

We move all terms containing y to the left, all other terms to the right

-13y=-53

y=-53/-13

y=4+1/13

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