3(6+7y)+2(1+5y)=42

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Solution for 3(6+7y)+2(1+5y)=42 equation: 



3(6+7y)+2(1+5y)=42

We move all terms to the left:

3(6+7y)+2(1+5y)-(42)=0

We add all the numbers together, and all the variables

3(7y+6)+2(5y+1)-42=0

We multiply parentheses

21y+10y+18+2-42=0

We add all the numbers together, and all the variables

31y-22=0

We move all terms containing y to the left, all other terms to the right

31y=22

y=22/31

y=22/31

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