3(6+7y)+2(1-5)=42

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Solution for 3(6+7y)+2(1-5)=42 equation: 



3(6+7y)+2(1-5)=42

We move all terms to the left:

3(6+7y)+2(1-5)-(42)=0

determiningTheFunctionDomain
3(6+7y)-42+2(1-5)=0

We add all the numbers together, and all the variables

3(7y+6)-42+2(-4)=0

We add all the numbers together, and all the variables

3(7y+6)-50=0

We multiply parentheses

21y+18-50=0

We add all the numbers together, and all the variables

21y-32=0

We move all terms containing y to the left, all other terms to the right

21y=32

y=32/21

y=1+11/21

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