3(6+b)(2+b)=

Solution for 3(6+b)(2+b)= equation:

Simplifying
3(6 + b)(2 + b) = 0

Multiply (6 + b) * (2 + b)
3(6(2 + b) + b(2 + b)) = 0
3((2 * 6 + b * 6) + b(2 + b)) = 0
3((12 + 6b) + b(2 + b)) = 0
3(12 + 6b + (2 * b + b * b)) = 0
3(12 + 6b + (2b + b2)) = 0

Combine like terms: 6b + 2b = 8b
3(12 + 8b + b2) = 0
(12 * 3 + 8b * 3 + b2 * 3) = 0
(36 + 24b + 3b2) = 0

Solving
36 + 24b + 3b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '3'.
3(12 + 8b + b2) = 0

Factor a trinomial.
3((6 + b)(2 + b)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(6 + b)' equal to zero and attempt to solve:

Simplifying
6 + b = 0

Solving
6 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + b = 0 + -6
b = 0 + -6

Combine like terms: 0 + -6 = -6
b = -6

Simplifying
b = -6
Subproblem 2
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Solution
b = {-6, -2}