3(6+c)=2(c-1)

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Solution for 3(6+c)=2(c-1) equation: 


Simplifying
3(6 + c) = 2(c + -1)
(6 * 3 + c * 3) = 2(c + -1)
(18 + 3c) = 2(c + -1)

Reorder the terms:
18 + 3c = 2(-1 + c)
18 + 3c = (-1 * 2 + c * 2)
18 + 3c = (-2 + 2c)

Solving
18 + 3c = -2 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
18 + 3c + -2c = -2 + 2c + -2c

Combine like terms: 3c + -2c = 1c
18 + 1c = -2 + 2c + -2c

Combine like terms: 2c + -2c = 0
18 + 1c = -2 + 0
18 + 1c = -2

Add '-18' to each side of the equation.
18 + -18 + 1c = -2 + -18

Combine like terms: 18 + -18 = 0
0 + 1c = -2 + -18
1c = -2 + -18

Combine like terms: -2 + -18 = -20
1c = -20

Divide each side by '1'.
c = -20

Simplifying
c = -20

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