3(6+c)=2(c-5)

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Solution for 3(6+c)=2(c-5) equation:


Simplifying
3(6 + c) = 2(c + -5)
(6 * 3 + c * 3) = 2(c + -5)
(18 + 3c) = 2(c + -5)

Reorder the terms:
18 + 3c = 2(-5 + c)
18 + 3c = (-5 * 2 + c * 2)
18 + 3c = (-10 + 2c)

Solving
18 + 3c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
18 + 3c + -2c = -10 + 2c + -2c

Combine like terms: 3c + -2c = 1c
18 + 1c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
18 + 1c = -10 + 0
18 + 1c = -10

Add '-18' to each side of the equation.
18 + -18 + 1c = -10 + -18

Combine like terms: 18 + -18 = 0
0 + 1c = -10 + -18
1c = -10 + -18

Combine like terms: -10 + -18 = -28
1c = -28

Divide each side by '1'.
c = -28

Simplifying
c = -28

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