3(6+f)=27

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Solution for 3(6+f)=27 equation: 



3(6+f)=27

We move all terms to the left:

3(6+f)-(27)=0

We add all the numbers together, and all the variables

3(f+6)-27=0

We multiply parentheses

3f+18-27=0

We add all the numbers together, and all the variables

3f-9=0

We move all terms containing f to the left, all other terms to the right

3f=9

f=9/3

f=3

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