3(6+x)=3(10-x)

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Solution for 3(6+x)=3(10-x) equation: 



3(6+x)=3(10-x)

We move all terms to the left:

3(6+x)-(3(10-x))=0

We add all the numbers together, and all the variables

3(x+6)-(3(-1x+10))=0

We multiply parentheses

3x-(3(-1x+10))+18=0



We calculate terms in parentheses: -(3(-1x+10)), so:

3(-1x+10)

We multiply parentheses

-3x+30

Back to the equation:

-(-3x+30)



We get rid of parentheses

3x+3x-30+18=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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