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3(6+x)=6(3+1/2x)
We move all terms to the left:
3(6+x)-(6(3+1/2x))=0
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3(x+6)-(6(1/2x+3))=0
We multiply parentheses
3x-(6(1/2x+3))+18=0
We multiply all the terms by the denominator
3x*2x+18*2x+3))-(6(1+3))=0
We add all the numbers together, and all the variables
3x*2x+18*2x+3))-(64)=0
We add all the numbers together, and all the variables
3x*2x+18*2x=0
Wy multiply elements
6x^2+36x=0
a = 6; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·6·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*6}=\frac{-72}{12} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*6}=\frac{0}{12} =0 $
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