3(6-1)=18-5(b+1)

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Solution for 3(6-1)=18-5(b+1) equation: 



3(6-1)=18-5(b+1)

We move all terms to the left:

3(6-1)-(18-5(b+1))=0

We add all the numbers together, and all the variables

-(18-5(b+1))+35=0



We calculate terms in parentheses: -(18-5(b+1)), so:

18-5(b+1)

determiningTheFunctionDomain
-5(b+1)+18

We multiply parentheses

-5b-5+18

We add all the numbers together, and all the variables

-5b+13

Back to the equation:

-(-5b+13)



We get rid of parentheses

5b-13+35=0

We add all the numbers together, and all the variables

5b+22=0

We move all terms containing b to the left, all other terms to the right

5b=-22

b=-22/5

b=-4+2/5

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