3(6-2x)+23=4-1/3(18x-3)

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Solution for 3(6-2x)+23=4-1/3(18x-3) equation: 



3(6-2x)+23=4-1/3(18x-3)

We move all terms to the left:

3(6-2x)+23-(4-1/3(18x-3))=0



Domain of the equation: 3(18x-3))!=0

x∈R



We add all the numbers together, and all the variables

3(-2x+6)-(4-1/3(18x-3))+23=0

We multiply parentheses

-6x-(4-1/3(18x-3))+18+23=0

We multiply all the terms by the denominator


-6x*3(18x-3))-(4+18*3(18x-3))+23*3(18x-1-3))=0

We add all the numbers together, and all the variables

-6x*3(18x-3))-(4+18*3(18x-3))+23*3(18x-4))=0

We add all the numbers together, and all the variables

-6x*3(18x-3))-(4+18*3(18x-3))+23*3(18x=0

Wy multiply elements

-18x^2(1+162x^2(1=0

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