3(6-2x)=7(8x-10)

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Solution for 3(6-2x)=7(8x-10) equation:



3(6-2x)=7(8x-10)
We move all terms to the left:
3(6-2x)-(7(8x-10))=0
We add all the numbers together, and all the variables
3(-2x+6)-(7(8x-10))=0
We multiply parentheses
-6x-(7(8x-10))+18=0
We calculate terms in parentheses: -(7(8x-10)), so:
7(8x-10)
We multiply parentheses
56x-70
Back to the equation:
-(56x-70)
We get rid of parentheses
-6x-56x+70+18=0
We add all the numbers together, and all the variables
-62x+88=0
We move all terms containing x to the left, all other terms to the right
-62x=-88
x=-88/-62
x=1+13/31

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