3(6-2x)=7(8x-10)

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Solution for 3(6-2x)=7(8x-10) equation: 



3(6-2x)=7(8x-10)

We move all terms to the left:

3(6-2x)-(7(8x-10))=0

We add all the numbers together, and all the variables

3(-2x+6)-(7(8x-10))=0

We multiply parentheses

-6x-(7(8x-10))+18=0



We calculate terms in parentheses: -(7(8x-10)), so:

7(8x-10)

We multiply parentheses

56x-70

Back to the equation:

-(56x-70)



We get rid of parentheses

-6x-56x+70+18=0

We add all the numbers together, and all the variables

-62x+88=0

We move all terms containing x to the left, all other terms to the right

-62x=-88

x=-88/-62

x=1+13/31

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