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3(6-x)+8=4-5(x+2)
We move all terms to the left:
3(6-x)+8-(4-5(x+2))=0
We add all the numbers together, and all the variables
3(-1x+6)-(4-5(x+2))+8=0
We multiply parentheses
-3x-(4-5(x+2))+18+8=0
We calculate terms in parentheses: -(4-5(x+2)), so:We add all the numbers together, and all the variables
4-5(x+2)
determiningTheFunctionDomain -5(x+2)+4
We multiply parentheses
-5x-10+4
We add all the numbers together, and all the variables
-5x-6
Back to the equation:
-(-5x-6)
-3x-(-5x-6)+26=0
We get rid of parentheses
-3x+5x+6+26=0
We add all the numbers together, and all the variables
2x+32=0
We move all terms containing x to the left, all other terms to the right
2x=-32
x=-32/2
x=-16
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