3(6-y)+4(2y-4)=y-2

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Solution for 3(6-y)+4(2y-4)=y-2 equation: 



3(6-y)+4(2y-4)=y-2

We move all terms to the left:

3(6-y)+4(2y-4)-(y-2)=0

We add all the numbers together, and all the variables

3(-1y+6)+4(2y-4)-(y-2)=0

We multiply parentheses

-3y+8y-(y-2)+18-16=0

We get rid of parentheses

-3y+8y-y+2+18-16=0

We add all the numbers together, and all the variables

4y+4=0

We move all terms containing y to the left, all other terms to the right

4y=-4

y=-4/4

y=-1

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