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3(6a)*a=3
We move all terms to the left:
3(6a)*a-(3)=0
Wy multiply elements
36a^2-3=0
a = 36; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·36·(-3)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*36}=\frac{0-12\sqrt{3}}{72} =-\frac{12\sqrt{3}}{72} =-\frac{\sqrt{3}}{6} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*36}=\frac{0+12\sqrt{3}}{72} =\frac{12\sqrt{3}}{72} =\frac{\sqrt{3}}{6} $
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