3(6a+5)=4(4a+5)

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Solution for 3(6a+5)=4(4a+5) equation: 



3(6a+5)=4(4a+5)

We move all terms to the left:

3(6a+5)-(4(4a+5))=0

We multiply parentheses

18a-(4(4a+5))+15=0



We calculate terms in parentheses: -(4(4a+5)), so:

4(4a+5)

We multiply parentheses

16a+20

Back to the equation:

-(16a+20)



We get rid of parentheses

18a-16a-20+15=0

We add all the numbers together, and all the variables

2a-5=0

We move all terms containing a to the left, all other terms to the right

2a=5

a=5/2

a=2+1/2

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