3(6b-4)=96

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Solution for 3(6b-4)=96 equation: 



3(6b-4)=96

We move all terms to the left:

3(6b-4)-(96)=0

We multiply parentheses

18b-12-96=0

We add all the numbers together, and all the variables

18b-108=0

We move all terms containing b to the left, all other terms to the right

18b=108

b=108/18

b=6

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