3(6r-4)+7(r-5)=60

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Solution for 3(6r-4)+7(r-5)=60 equation: 



3(6r-4)+7(r-5)=60

We move all terms to the left:

3(6r-4)+7(r-5)-(60)=0

We multiply parentheses

18r+7r-12-35-60=0

We add all the numbers together, and all the variables

25r-107=0

We move all terms containing r to the left, all other terms to the right

25r=107

r=107/25

r=4+7/25

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